已知-1已知-1
已知-11、-1-2 => 5>5x>-10 => 15>5x+10>01>x>-2 => 0>x-1>-32、由1可知5x+10>0 x-1
-1<1-2x<5 , 根据 -1<1-2x,解出x<1,根据1-2x<5,解出-20<5x+10<15 -3