3x+4y-5=0 x^2+y^2=1求x.y
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3x+4y-5=0 x^2+y^2=1求x.y
3x+4y-5=0 x^2+y^2=1求x.y
3x+4y-5=0 x^2+y^2=1求x.y
{3x+4y-5=0 (1)
x^2+y^2=1 (2)
由(1)
x=(5-4y)/3 (3)
代入(2)
(5-4y)^2/9+y^2=1
(5-4y)^2+9y^2=9
25-40y+16y^2+9y^2=9
25y^2--40y+16=0
(5y-4)^2=0
5y-4=0
y=4/5
代入(3)解得x=3/5
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