y=2sin(2x+π/3)(-π/6≤x≤π/6)求值域
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y=2sin(2x+π/3)(-π/6≤x≤π/6)求值域
y=2sin(2x+π/3)(-π/6≤x≤π/6)求值域
y=2sin(2x+π/3)(-π/6≤x≤π/6)求值域
因为 -π/6≤x≤π/6 所以0 ≤2x+π/3≤2π/3
所以 0≤2sin(2x+π/3)≤2
-π/6≤x≤π/6
-π/3≤2x≤π/3
0≤2x+π/3≤2π/3
0≤sin(2x+π/3)≤1
0≤2sin(2x+π/3)≤2
值域为[0,2]
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