y=tan(2x-π/4)+tan(2x+π/4)的最小正周期是?最好用切割化弦做一下。
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![y=tan(2x-π/4)+tan(2x+π/4)的最小正周期是?最好用切割化弦做一下。](/uploads/image/z/10138205-29-5.jpg?t=y%3Dtan%282x-%CF%80%2F4%29%2Btan%282x%2B%CF%80%2F4%29%E7%9A%84%E6%9C%80%E5%B0%8F%E6%AD%A3%E5%91%A8%E6%9C%9F%E6%98%AF%3F%E6%9C%80%E5%A5%BD%E7%94%A8%E5%88%87%E5%89%B2%E5%8C%96%E5%BC%A6%E5%81%9A%E4%B8%80%E4%B8%8B%E3%80%82)
y=tan(2x-π/4)+tan(2x+π/4)的最小正周期是?最好用切割化弦做一下。
y=tan(2x-π/4)+tan(2x+π/4)的最小正周期是?
最好用切割化弦做一下。
y=tan(2x-π/4)+tan(2x+π/4)的最小正周期是?最好用切割化弦做一下。
y=sin(2x-π/4)/cos(2x-π/4)+sin(2x+π/4)/cos(2x+π/4)
=[sin(2x-π/4)cos(2x+π/4)+cos(2x-π/4)sin(2x+π/4)] / cos(2x+π/4)cos(2x-π/4)
=2sin4x/cos4x
=2tan4x
最小正周期是T=π/4
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