求三题一元二次方程因式分解过程1.(6-a)(9-a)x^2-(117-15a)x+54=02.(a-1)x^2+2x-a-1=03.(k^2-1)x^2-3(3k-1)x+18=01.【(6-a)x-9】·【(9-a)x-6】=02.(x-1)·【(a-1)x+(a+1)】=03.【(k+1)x-6】·
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![求三题一元二次方程因式分解过程1.(6-a)(9-a)x^2-(117-15a)x+54=02.(a-1)x^2+2x-a-1=03.(k^2-1)x^2-3(3k-1)x+18=01.【(6-a)x-9】·【(9-a)x-6】=02.(x-1)·【(a-1)x+(a+1)】=03.【(k+1)x-6】·](/uploads/image/z/10139267-11-7.jpg?t=%E6%B1%82%E4%B8%89%E9%A2%98%E4%B8%80%E5%85%83%E4%BA%8C%E6%AC%A1%E6%96%B9%E7%A8%8B%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3%E8%BF%87%E7%A8%8B1.%EF%BC%886-a%EF%BC%89%EF%BC%889-a%EF%BC%89x%5E2-%EF%BC%88117-15a%EF%BC%89x%2B54%3D02.%EF%BC%88a-1%EF%BC%89x%5E2%2B2x-a-1%3D03.%EF%BC%88k%5E2-1%EF%BC%89x%5E2-3%EF%BC%883k-1%EF%BC%89x%2B18%3D01.%E3%80%90%EF%BC%886-a%EF%BC%89x-9%E3%80%91%C2%B7%E3%80%90%EF%BC%889-a%EF%BC%89x-6%E3%80%91%3D02.%EF%BC%88x-1%EF%BC%89%C2%B7%E3%80%90%EF%BC%88a-1%EF%BC%89x%2B%EF%BC%88a%2B1%EF%BC%89%E3%80%91%3D03.%E3%80%90%EF%BC%88k%2B1%EF%BC%89x-6%E3%80%91%C2%B7)
求三题一元二次方程因式分解过程1.(6-a)(9-a)x^2-(117-15a)x+54=02.(a-1)x^2+2x-a-1=03.(k^2-1)x^2-3(3k-1)x+18=01.【(6-a)x-9】·【(9-a)x-6】=02.(x-1)·【(a-1)x+(a+1)】=03.【(k+1)x-6】·
求三题一元二次方程因式分解过程
1.(6-a)(9-a)x^2-(117-15a)x+54=0
2.(a-1)x^2+2x-a-1=0
3.(k^2-1)x^2-3(3k-1)x+18=0
1.【(6-a)x-9】·【(9-a)x-6】=0
2.(x-1)·【(a-1)x+(a+1)】=0
3.【(k+1)x-6】·【(k-1)x-3】=0
求三题一元二次方程因式分解过程1.(6-a)(9-a)x^2-(117-15a)x+54=02.(a-1)x^2+2x-a-1=03.(k^2-1)x^2-3(3k-1)x+18=01.【(6-a)x-9】·【(9-a)x-6】=02.(x-1)·【(a-1)x+(a+1)】=03.【(k+1)x-6】·
.(6-a)(9-a)x²-(117-15a)x+54=0
[(6-a)x-6][(9-a)x-9]=0
十字相乘法
(6-a)x -6
╳
(9-a)x -9
(a-1)x²+2x-a-1=0
(x-1)[(a-1)x+(a+1)]=0
十字相乘法
x -1
╳
(a-1)x (a+1)
.(k²-1)x²-3(3k-1)x+18=0
(k+1)(k-1)x²-3(3k-1)x+18=0
.[(k+1)x-6][(k-1)x-3]=0
十字相乘法
(k+1)x -6
╳
(k-1)x -3
十字相乘法
1)6-a -9
X
9-a -6 交叉相乘之和 -36+6a+(-81+9a)=15a-117=-(117-15a)=一次项系数
以下两题道理相同。