已知x+2y=11,x-2y=4,求分式[x/(x^2-2xy+y^2)]÷(x^2+xy+y^2)/(x^3-y^3)+[(2x+2y)/(x-y)-2]的值⊙ o ⊙
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![已知x+2y=11,x-2y=4,求分式[x/(x^2-2xy+y^2)]÷(x^2+xy+y^2)/(x^3-y^3)+[(2x+2y)/(x-y)-2]的值⊙ o ⊙](/uploads/image/z/1014598-46-8.jpg?t=%E5%B7%B2%E7%9F%A5x%2B2y%3D11%2Cx-2y%3D4%2C%E6%B1%82%E5%88%86%E5%BC%8F%5Bx%2F%28x%5E2-2xy%2By%5E2%29%5D%C3%B7%28x%5E2%2Bxy%2By%5E2%EF%BC%89%2F%EF%BC%88x%5E3-y%5E3%EF%BC%89%2B%5B%282x%2B2y%29%2F%28x-y%29-2%5D%E7%9A%84%E5%80%BC%E2%8A%99+o+%E2%8A%99)
已知x+2y=11,x-2y=4,求分式[x/(x^2-2xy+y^2)]÷(x^2+xy+y^2)/(x^3-y^3)+[(2x+2y)/(x-y)-2]的值⊙ o ⊙
已知x+2y=11,x-2y=4,求分式[x/(x^2-2xy+y^2)]÷(x^2+xy+y^2)/(x^3-y^3)+[(2x+2y)/(x-y)-2]的值
⊙ o ⊙
已知x+2y=11,x-2y=4,求分式[x/(x^2-2xy+y^2)]÷(x^2+xy+y^2)/(x^3-y^3)+[(2x+2y)/(x-y)-2]的值⊙ o ⊙
神!自己慢慢算.
这种题适合混时间用!
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