已知x、y满足x²+y²-6x+2y+10=0,求³√(x²-y²)的值.
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/20 17:31:21
![已知x、y满足x²+y²-6x+2y+10=0,求³√(x²-y²)的值.](/uploads/image/z/1084799-47-9.jpg?t=%E5%B7%B2%E7%9F%A5x%E3%80%81y%E6%BB%A1%E8%B6%B3x%26%23178%3B%2By%26%23178%3B-6x%2B2y%2B10%3D0%2C%E6%B1%82%26%23179%3B%E2%88%9A%EF%BC%88x%26%23178%3B-y%26%23178%3B%EF%BC%89%E7%9A%84%E5%80%BC.)
已知x、y满足x²+y²-6x+2y+10=0,求³√(x²-y²)的值.
已知x、y满足x²+y²-6x+2y+10=0,求³√(x²-y²)的值.
已知x、y满足x²+y²-6x+2y+10=0,求³√(x²-y²)的值.
x²+y²-6x+2y+10=0
(x²-6x+9)+(y²+2y+1)=0
(x-3)²+(y+1)²=0
∵(x-3)²≥0,(y+1)²≥0
∴x-3=0,y+1=0
∴x=3,y=-1
∴³√(x²-y²)=³√[3²-(-1)²]=³√8=2
x²+y²-6x+2y+10=0
→(x-3)^2+(y+1)^2=0
→x=3,y=-1
3√(x^2-y^2)=3√(9-1)=2
不懂, 请追问,祝愉快O(∩_∩)O~