若:1+1/2^2+1/3^2+1/4^2+.+1/n^2=A 求 1/1^2+1/3^2+1/5^2+.+1/(2n-1)^2=?
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![若:1+1/2^2+1/3^2+1/4^2+.+1/n^2=A 求 1/1^2+1/3^2+1/5^2+.+1/(2n-1)^2=?](/uploads/image/z/11521085-5-5.jpg?t=%E8%8B%A5%EF%BC%9A1%2B1%2F2%5E2%2B1%2F3%5E2%2B1%2F4%5E2%2B.%2B1%2Fn%5E2%3DA+%E6%B1%82+1%2F1%5E2%2B1%2F3%5E2%2B1%2F5%5E2%2B.%2B1%2F%282n-1%29%5E2%3D%3F)
若:1+1/2^2+1/3^2+1/4^2+.+1/n^2=A 求 1/1^2+1/3^2+1/5^2+.+1/(2n-1)^2=?
若:1+1/2^2+1/3^2+1/4^2+.+1/n^2=A 求 1/1^2+1/3^2+1/5^2+.+1/(2n-1)^2=?
若:1+1/2^2+1/3^2+1/4^2+.+1/n^2=A 求 1/1^2+1/3^2+1/5^2+.+1/(2n-1)^2=?
若:1+1/2^2+1/3^2+1/4^2+.+1/n^2=A
则 1/1^2+1/3^2+1/5^2+.+1/(2n-1)^2=A+.1/(n+1)^2+.+1/(2n-1)^2