若|ab-2|+|b-1|=0,试求1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+…+1/(a+2003)(b+2003)若|ab-2|+|b-1|=0,试求 1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+…+1/(a+2003)(b+2003)
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/26 01:09:03
![若|ab-2|+|b-1|=0,试求1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+…+1/(a+2003)(b+2003)若|ab-2|+|b-1|=0,试求 1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+…+1/(a+2003)(b+2003)](/uploads/image/z/12041120-56-0.jpg?t=%E8%8B%A5%7Cab-2%7C%2B%7Cb-1%7C%3D0%2C%E8%AF%95%E6%B1%821%2Fab%2B1%2F%28a%2B1%29%28b%2B1%29%2B1%2F%28a%2B2%29%28b%2B2%29%2B%E2%80%A6%2B1%2F%28a%2B2003%29%28b%2B2003%29%E8%8B%A5%7Cab-2%7C%2B%7Cb-1%7C%3D0%2C%E8%AF%95%E6%B1%82+1%2Fab%2B1%2F%28a%2B1%29%28b%2B1%29%2B1%2F%28a%2B2%29%28b%2B2%29%2B%E2%80%A6%2B1%2F%28a%2B2003%29%28b%2B2003%29)
若|ab-2|+|b-1|=0,试求1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+…+1/(a+2003)(b+2003)若|ab-2|+|b-1|=0,试求 1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+…+1/(a+2003)(b+2003)
若|ab-2|+|b-1|=0,试求1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+…+1/(a+2003)(b+2003)
若|ab-2|+|b-1|=0,试求 1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+…+1/(a+2003)(b+2003)
若|ab-2|+|b-1|=0,试求1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+…+1/(a+2003)(b+2003)若|ab-2|+|b-1|=0,试求 1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+…+1/(a+2003)(b+2003)
易知ab=2 b=1 所以a=2 所以原式子就变成了1/2+1/2*3+1/3*4+.+1/2004*2005=1-1/2005=2004/2005 这个解法你应该会吧 有这么一个式子就是 1/(n+1)n=1/n-1/(n+1)