9.若(1+x)+(1+x)2+…+(1+x)n=a0+a1(1-x)+a2(1-x)2+…+an(1-x)n则a0-a1+a2-…+(-1)nan等于( )
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![9.若(1+x)+(1+x)2+…+(1+x)n=a0+a1(1-x)+a2(1-x)2+…+an(1-x)n则a0-a1+a2-…+(-1)nan等于( )](/uploads/image/z/12083592-48-2.jpg?t=9%EF%BC%8E%E8%8B%A5%EF%BC%881%2Bx%EF%BC%89%2B%EF%BC%881%2Bx%EF%BC%892%2B%E2%80%A6%2B%EF%BC%881%2Bx%EF%BC%89n%3Da0%2Ba1%EF%BC%881-x%EF%BC%89%2Ba2%EF%BC%881-x%EF%BC%892%2B%E2%80%A6%2Ban%EF%BC%881-x%EF%BC%89n%E5%88%99a0-a1%2Ba2-%E2%80%A6%2B%EF%BC%88-1%EF%BC%89nan%E7%AD%89%E4%BA%8E%EF%BC%88%E3%80%80%E3%80%80%EF%BC%89)
9.若(1+x)+(1+x)2+…+(1+x)n=a0+a1(1-x)+a2(1-x)2+…+an(1-x)n则a0-a1+a2-…+(-1)nan等于( )
9.若(1+x)+(1+x)2+…+(1+x)n=a0+a1(1-x)+a2(1-x)2+…+an(
1-x)n则a0-a1+a2-…+(-1)nan等于( )
9.若(1+x)+(1+x)2+…+(1+x)n=a0+a1(1-x)+a2(1-x)2+…+an(1-x)n则a0-a1+a2-…+(-1)nan等于( )
令x=2原式=3+3^2+3^3+……+3^n=(3^(n+1)-3)/2