已知数列{an}满足a1=1,an+a(n+1)=(1/3)的n次方(n∈N),Sn=a1+3a2+3²a3……+3n-1次方an,则4Sn-3的n次方×an=
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![已知数列{an}满足a1=1,an+a(n+1)=(1/3)的n次方(n∈N),Sn=a1+3a2+3²a3……+3n-1次方an,则4Sn-3的n次方×an=](/uploads/image/z/1240628-68-8.jpg?t=%E5%B7%B2%E7%9F%A5%E6%95%B0%E5%88%97%7Ban%7D%E6%BB%A1%E8%B6%B3a1%3D1%2Can%2Ba%EF%BC%88n%2B1%EF%BC%89%3D%EF%BC%881%2F3%EF%BC%89%E7%9A%84n%E6%AC%A1%E6%96%B9%EF%BC%88n%E2%88%88N%EF%BC%89%2CSn%3Da1%2B3a2%2B3%26%23178%3Ba3%E2%80%A6%E2%80%A6%2B3n-1%E6%AC%A1%E6%96%B9an%2C%E5%88%994Sn-3%E7%9A%84n%E6%AC%A1%E6%96%B9%C3%97an%3D)
已知数列{an}满足a1=1,an+a(n+1)=(1/3)的n次方(n∈N),Sn=a1+3a2+3²a3……+3n-1次方an,则4Sn-3的n次方×an=
已知数列{an}满足a1=1,an+a(n+1)=(1/3)的n次方(n∈N),Sn=a1+3a2+3²a3……+3n-1次方an,
则4Sn-3的n次方×an=
已知数列{an}满足a1=1,an+a(n+1)=(1/3)的n次方(n∈N),Sn=a1+3a2+3²a3……+3n-1次方an,则4Sn-3的n次方×an=
答案是n,你把Sn写出来,把3Sn写出来,两式相加,把1式第一项和2式第一项相加,1式第二项和2式第三项相加,以此类推,每一项都是1,所以4Sn=n+(3n-1次方)*an,所以答案为n.
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