设x>1且x²+2x-11=0,则log2(x-1)+log2(x+3)=?(须写最简结果)
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设x>1且x²+2x-11=0,则log2(x-1)+log2(x+3)=?(须写最简结果)
设x>1且x²+2x-11=0,则log2(x-1)+log2(x+3)=?(须写最简结果)
设x>1且x²+2x-11=0,则log2(x-1)+log2(x+3)=?(须写最简结果)
答:
x>1,x²+2x-11=0
x²+2x=11
log2(x-1)+log2(x+3)
=log2[(x-1)(x+3)]
=log2(x²+2x-3)
=log2(11-3)
=log2(8)
=log2(2³)
=3
设x>1且x²+2x-11=0,则
log2(x-1)+log2(x+3)
=log2(x-1)(x+3)
=log2(x²+2x-3)
=log2(11-3)
=log2(8)
=3;
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设x>1且x²+2x-11=0,则
log2(x-1)+log2(x+3)
=log2(x-1)(x+3)
=log2(x²+2x-3)
=log2(11-3)
=log2(8)
=3;
您好,很高兴为您解答,skyhunter002为您答疑解惑
如果本题有什么不明白可以追问,如果满意记得采纳
如果有其他问题请采纳本题后另发点击向我求助,答题不易,请谅解,谢谢。
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