作业帮设函数f(x)=√2-(x+3)/x+1,的定义域为A,g(x)=lg[(x-a-1)(2a-x)],(a
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![设函数f(x)=√2-(x+3)/x+1,的定义域为A,g(x)=lg[(x-a-1)(2a-x)],(a](/uploads/image/z/1264793-41-3.jpg?t=%E8%AE%BE%E5%87%BD%E6%95%B0f%28x%29%3D%E2%88%9A2-%28x%2B3%29%2Fx%2B1%2C%E7%9A%84%E5%AE%9A%E4%B9%89%E5%9F%9F%E4%B8%BAA%2Cg%28x%29%3Dlg%5B%28x-a-1%29%282a-x%29%5D%2C%28a)
设函数f(x)=√2-(x+3)/x+1,的定义域为A,g(x)=lg[(x-a-1)(2a-x)],(a
设函数f(x)=√2-(x+3)/x+1,的定义域为A,g(x)=lg[(x-a-1)(2a-x)],(a
设函数f(x)=√2-(x+3)/x+1,的定义域为A,g(x)=lg[(x-a-1)(2a-x)],(a
2-(x+3)/(x+1)>=0
(2x+2-x-3)/(x+1)>=0
(x-1)(x+1)>=0
x+1在分母,不等于0
所以A={x|x>=1,x