已知Ia+1I+(a+b-2)²=0,化简ab-2{ab-[3a²b-(4ab²+0.5ab)-3a²b]}3ab²,并求出它的值,
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![已知Ia+1I+(a+b-2)²=0,化简ab-2{ab-[3a²b-(4ab²+0.5ab)-3a²b]}3ab²,并求出它的值,](/uploads/image/z/12877501-13-1.jpg?t=%E5%B7%B2%E7%9F%A5Ia%2B1I%2B%28a%2Bb-2%29%26%23178%3B%3D0%2C%E5%8C%96%E7%AE%80ab-2%EF%BD%9Bab-%5B3a%26%23178%3Bb-%284ab%26%23178%3B%2B0.5ab%29-3a%26%23178%3Bb%5D%EF%BD%9D3ab%26%23178%3B%2C%E5%B9%B6%E6%B1%82%E5%87%BA%E5%AE%83%E7%9A%84%E5%80%BC%2C)
已知Ia+1I+(a+b-2)²=0,化简ab-2{ab-[3a²b-(4ab²+0.5ab)-3a²b]}3ab²,并求出它的值,
已知Ia+1I+(a+b-2)²=0,化简ab-2{ab-[3a²b-(4ab²+0.5ab)-3a²b]}3ab²,并求出它的值,
已知Ia+1I+(a+b-2)²=0,化简ab-2{ab-[3a²b-(4ab²+0.5ab)-3a²b]}3ab²,并求出它的值,
已知Ia+1I+(a+b-2)²=0,则有:
a+1=0且a+b-2=0
解得:a=-1,b=2-a=3
所以:
ab-2{ab-[3a²b-(4ab²+0.5ab)-3a²b]}+3ab²
=ab-2[ab-(3a²b-4ab²-0.5ab-3a²b)] +3ab²
=ab-2[ab-(-4ab²-0.5ab)] +3ab²
=ab-2(ab+4ab²+0.5ab) +3ab²
=ab-2(1.5ab+4ab²) +3ab²
=ab-3ab-8ab² +3ab²
=-2ab-5ab²
=-ab(2+5b)
=-(-1)*3*(2+15)
=3*17
=51