已知p=2a^3-abc,Q=b^2-c^2+abc,M=a^3+2b^2-abc,且(a+7)^2+|b-8|+|c|=0,求p-[2Q-3(M-P)]的值..._O_../_\o/_\ ./H\ .(=O=).U.
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![已知p=2a^3-abc,Q=b^2-c^2+abc,M=a^3+2b^2-abc,且(a+7)^2+|b-8|+|c|=0,求p-[2Q-3(M-P)]的值..._O_../_\o/_\ ./H\ .(=O=).U.](/uploads/image/z/13350939-51-9.jpg?t=%E5%B7%B2%E7%9F%A5p%3D2a%5E3-abc%2CQ%3Db%5E2-c%5E2%2Babc%2CM%3Da%5E3%2B2b%5E2-abc%2C%E4%B8%94%EF%BC%88a%2B7%29%5E2%2B%7Cb-8%7C%2B%7Cc%7C%3D0%2C%E6%B1%82p-%5B2Q-3%28M-P%29%5D%E7%9A%84%E5%80%BC..._O_..%2F_%5Co%2F_%5C+.%2FH%5C+.%28%3DO%3D%29.U.)
已知p=2a^3-abc,Q=b^2-c^2+abc,M=a^3+2b^2-abc,且(a+7)^2+|b-8|+|c|=0,求p-[2Q-3(M-P)]的值..._O_../_\o/_\ ./H\ .(=O=).U.
已知p=2a^3-abc,Q=b^2-c^2+abc,M=a^3+2b^2-abc,且(a+7)^2+|b-8|+|c|=0,求p-[2Q-3(M-P)]的值.
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/_\o/_\ .
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(=O=).
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已知p=2a^3-abc,Q=b^2-c^2+abc,M=a^3+2b^2-abc,且(a+7)^2+|b-8|+|c|=0,求p-[2Q-3(M-P)]的值..._O_../_\o/_\ ./H\ .(=O=).U.
因为(a+7)^2+|b-8|+|c|=0.又因为(a+7)^2≥0 |b-8|≥0 |c|≥0
所以a=-7 b=8 c=0
所以P=-686 Q=64 M=-215
所以799,