若奇函数f(x)满足f(x+2)=-f(x),且f(x)在x∈(0,1)时,f(x)=x^-2,则f(-6.5)=
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![若奇函数f(x)满足f(x+2)=-f(x),且f(x)在x∈(0,1)时,f(x)=x^-2,则f(-6.5)=](/uploads/image/z/13353713-17-3.jpg?t=%E8%8B%A5%E5%A5%87%E5%87%BD%E6%95%B0f%28x%29%E6%BB%A1%E8%B6%B3f%28x%2B2%29%3D-f%28x%29%2C%E4%B8%94f%28x%29%E5%9C%A8x%E2%88%88%280%2C1%29%E6%97%B6%2Cf%28x%29%3Dx%5E-2%2C%E5%88%99f%28-6.5%29%3D)
若奇函数f(x)满足f(x+2)=-f(x),且f(x)在x∈(0,1)时,f(x)=x^-2,则f(-6.5)=
若奇函数f(x)满足f(x+2)=-f(x),且f(x)在x∈(0,1)时,f(x)=x^-2,则f(-6.5)=
若奇函数f(x)满足f(x+2)=-f(x),且f(x)在x∈(0,1)时,f(x)=x^-2,则f(-6.5)=
f(-6.5)=-f(6.5)=f(4.5)=-f(2.5)=f(0.5)=(0.5)^2-2=-1.75
函数周期为2
所以(-6.5)=-f(6.5)=f(4.5)=-f(2.5)=f(0.5)=(0.5)^2-2=-1.75
啊啊啊啊。。晕了、、
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