已知集合a={y/y=√4-x^2,x,y∈R},B={y/y=√4x-x^2,x,y∈R},则A∩B=?
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![已知集合a={y/y=√4-x^2,x,y∈R},B={y/y=√4x-x^2,x,y∈R},则A∩B=?](/uploads/image/z/13391580-12-0.jpg?t=%E5%B7%B2%E7%9F%A5%E9%9B%86%E5%90%88a%3D%EF%BD%9By%2Fy%3D%E2%88%9A4-x%5E2%2Cx%2Cy%E2%88%88R%EF%BD%9D%2CB%3D%EF%BD%9By%2Fy%3D%E2%88%9A4x-x%5E2%2Cx%2Cy%E2%88%88R%EF%BD%9D%2C%E5%88%99A%E2%88%A9B%3D%3F)
已知集合a={y/y=√4-x^2,x,y∈R},B={y/y=√4x-x^2,x,y∈R},则A∩B=?
已知集合a={y/y=√4-x^2,x,y∈R},B={y/y=√4x-x^2,x,y∈R},则A∩B=?
已知集合a={y/y=√4-x^2,x,y∈R},B={y/y=√4x-x^2,x,y∈R},则A∩B=?
√3
求A,B的交集可以转换为求√4-x^2=√4x-x^2的解
解得x=1,满足4-x^2≥0,4x-x^2≥0
y=√3
即A∩B=√3