已知字母a,b满足√a-1+√b-2=0求ab分之1+(a+1)(b+1)分之1+(a+2)(b+2)分之1+...+(a+2011)(b+2011)分之1的值
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/21 06:21:15
![已知字母a,b满足√a-1+√b-2=0求ab分之1+(a+1)(b+1)分之1+(a+2)(b+2)分之1+...+(a+2011)(b+2011)分之1的值](/uploads/image/z/13397048-8-8.jpg?t=%E5%B7%B2%E7%9F%A5%E5%AD%97%E6%AF%8Da%2Cb%E6%BB%A1%E8%B6%B3%E2%88%9Aa-1%2B%E2%88%9Ab-2%3D0%E6%B1%82ab%E5%88%86%E4%B9%8B1%2B%EF%BC%88a%2B1%EF%BC%89%EF%BC%88b%2B1%EF%BC%89%E5%88%86%E4%B9%8B1%2B%EF%BC%88a%2B2%EF%BC%89%EF%BC%88b%2B2%EF%BC%89%E5%88%86%E4%B9%8B1%2B...%2B%EF%BC%88a%2B2011%EF%BC%89%EF%BC%88b%2B2011%EF%BC%89%E5%88%86%E4%B9%8B1%E7%9A%84%E5%80%BC)
已知字母a,b满足√a-1+√b-2=0求ab分之1+(a+1)(b+1)分之1+(a+2)(b+2)分之1+...+(a+2011)(b+2011)分之1的值
已知字母a,b满足√a-1+√b-2=0
求ab分之1+(a+1)(b+1)分之1+(a+2)(b+2)分之1+...+(a+2011)(b+2011)分之1的值
已知字母a,b满足√a-1+√b-2=0求ab分之1+(a+1)(b+1)分之1+(a+2)(b+2)分之1+...+(a+2011)(b+2011)分之1的值
√a-1+√b-2=0
所以a-1=0
b-2=0
a=1,b=2
所以原式=1/1×2+1/2×3+……+1/2012×2013
=1-1/2+1/2-1/3+……+1/2012-1/2013
=1-1/2013
=2012/2013
亲,记得给好评哦
√a-1+√b-2=0
说明a=1
b=2
代入即可
赶快采纳!