那位大大 急 用c语言做 给定程序功能是计算S=f(-n)+f(-n+1)+…+f(0)+f(1)+f(2)+…+f(n)的值给定程序功能是计算S=f(-n)+f(-n+1)+…+f(0)+f(1)+f(2)+…+f(n)的值.例如,当n为5时,函数值应为:10.407143.┌(x+1)/(x-2) x>0 f(
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![那位大大 急 用c语言做 给定程序功能是计算S=f(-n)+f(-n+1)+…+f(0)+f(1)+f(2)+…+f(n)的值给定程序功能是计算S=f(-n)+f(-n+1)+…+f(0)+f(1)+f(2)+…+f(n)的值.例如,当n为5时,函数值应为:10.407143.┌(x+1)/(x-2) x>0 f(](/uploads/image/z/13895988-60-8.jpg?t=%E9%82%A3%E4%BD%8D%E5%A4%A7%E5%A4%A7+%E6%80%A5+%E7%94%A8c%E8%AF%AD%E8%A8%80%E5%81%9A+%E7%BB%99%E5%AE%9A%E7%A8%8B%E5%BA%8F%E5%8A%9F%E8%83%BD%E6%98%AF%E8%AE%A1%E7%AE%97S%3Df%28-n%29%2Bf%28-n%2B1%29%2B%E2%80%A6%2Bf%280%29%2Bf%281%29%2Bf%282%29%2B%E2%80%A6%2Bf%28n%29%E7%9A%84%E5%80%BC%E7%BB%99%E5%AE%9A%E7%A8%8B%E5%BA%8F%E5%8A%9F%E8%83%BD%E6%98%AF%E8%AE%A1%E7%AE%97S%3Df%28-n%29%2Bf%28-n%2B1%29%2B%E2%80%A6%2Bf%280%29%2Bf%281%29%2Bf%282%29%2B%E2%80%A6%2Bf%28n%29%E7%9A%84%E5%80%BC.%E4%BE%8B%E5%A6%82%2C%E5%BD%93n%E4%B8%BA5%E6%97%B6%2C%E5%87%BD%E6%95%B0%E5%80%BC%E5%BA%94%E4%B8%BA%3A10.407143.%E2%94%8C%28x%2B1%29%2F%28x-2%29+x%3E0+f%28)
那位大大 急 用c语言做 给定程序功能是计算S=f(-n)+f(-n+1)+…+f(0)+f(1)+f(2)+…+f(n)的值给定程序功能是计算S=f(-n)+f(-n+1)+…+f(0)+f(1)+f(2)+…+f(n)的值.例如,当n为5时,函数值应为:10.407143.┌(x+1)/(x-2) x>0 f(
那位大大 急 用c语言做 给定程序功能是计算S=f(-n)+f(-n+1)+…+f(0)+f(1)+f(2)+…+f(n)的值
给定程序功能是计算S=f(-n)+f(-n+1)+…+f(0)+f(1)+f(2)+…+f(n)的值.
例如,当n为5时,函数值应为:10.407143.
┌(x+1)/(x-2) x>0
f(x) = ┤0 x=0 或 x=2
└(x-1)/(x-2) x
那位大大 急 用c语言做 给定程序功能是计算S=f(-n)+f(-n+1)+…+f(0)+f(1)+f(2)+…+f(n)的值给定程序功能是计算S=f(-n)+f(-n+1)+…+f(0)+f(1)+f(2)+…+f(n)的值.例如,当n为5时,函数值应为:10.407143.┌(x+1)/(x-2) x>0 f(
计算过程分成4段,
f(-n)到f(-1);
f(0);
f(1);
f(2);
f(3)到f(n);
f(-n)到f(-1)你试下这个:
using System;
public class program
{
public static void Main()
{
float s1, s2=0, s3, s4=0, s=0;
int i, j;
int n;
string str;
Console.WriteLine("请输入要计算的整数:");
str = Console.ReadLine();
System.Text.ASCIIEncoding ascii = new System.Text.ASCIIEncoding();
byte[] bytestr = ascii.GetBytes(str);
n = Convert.ToInt32(str);
if (n >= 1)
{
for (i = 1; i