若函数f(x)=cosωxcos(π/2-ωx),ω>0,最小正周期为π,则ω=
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![若函数f(x)=cosωxcos(π/2-ωx),ω>0,最小正周期为π,则ω=](/uploads/image/z/13910533-61-3.jpg?t=%E8%8B%A5%E5%87%BD%E6%95%B0f%28x%29%3Dcos%CF%89xcos%28%CF%80%2F2-%CF%89x%29%2C%CF%89%3E0%2C%E6%9C%80%E5%B0%8F%E6%AD%A3%E5%91%A8%E6%9C%9F%E4%B8%BA%CF%80%2C%E5%88%99%CF%89%3D)
若函数f(x)=cosωxcos(π/2-ωx),ω>0,最小正周期为π,则ω=
若函数f(x)=cosωxcos(π/2-ωx),ω>0,最小正周期为π,则ω=
若函数f(x)=cosωxcos(π/2-ωx),ω>0,最小正周期为π,则ω=
f(x)=cosωxcos(π/2-ωx)=cosωxsin(ωx)=1/2sin2wx
T=2π/(2w)=π
所以:w=1