cosC+√2 sinC=√3 ,与cos^2C+sin^2C=1联立 sinC= √6/3 求两式联立祥解过程,我怎么带都求不出啊
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![cosC+√2 sinC=√3 ,与cos^2C+sin^2C=1联立 sinC= √6/3 求两式联立祥解过程,我怎么带都求不出啊](/uploads/image/z/14657137-25-7.jpg?t=cosC%2B%E2%88%9A2+sinC%3D%E2%88%9A3+%2C%E4%B8%8Ecos%5E2C%2Bsin%5E2C%3D1%E8%81%94%E7%AB%8B+sinC%3D+%E2%88%9A6%2F3+%E6%B1%82%E4%B8%A4%E5%BC%8F%E8%81%94%E7%AB%8B%E7%A5%A5%E8%A7%A3%E8%BF%87%E7%A8%8B%2C%E6%88%91%E6%80%8E%E4%B9%88%E5%B8%A6%E9%83%BD%E6%B1%82%E4%B8%8D%E5%87%BA%E5%95%8A)
cosC+√2 sinC=√3 ,与cos^2C+sin^2C=1联立 sinC= √6/3 求两式联立祥解过程,我怎么带都求不出啊
cosC+√2 sinC=√3 ,与cos^2C+sin^2C=1联立 sinC= √6/3 求两式联立祥解过程,我怎么带都求不出啊
cosC+√2 sinC=√3 ,与cos^2C+sin^2C=1联立 sinC= √6/3 求两式联立祥解过程,我怎么带都求不出啊
∵cosC+√2sinC=√3
∴cosC=√3-√2sinC
又cos²C+sin²C=1
∴(√3-√2sinC)²+sin²C=1
即3sin²C-2√6sinC+2=0
则(√3sinC-√2)²=0
故√3sinC=√2
∴sinC=√2/√3=√6/3