已知:RT三角形ABC中,∠C=90°,AC=4,cotB=根号3,MN=2,QM垂直于AB,PN平行于QM,设AM=x,MNPO的面积为y1) 当X=5/6时,球PB的长2)求y关于x 的函数解析式,并写出X的取值范围.3)三角形PCQ与三角形QMA能相似吗?若能

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已知:RT三角形ABC中,∠C=90°,AC=4,cotB=根号3,MN=2,QM垂直于AB,PN平行于QM,设AM=x,MNPO的面积为y1) 当X=5/6时,球PB的长2)求y关于x 的函数解析式,并写出X的取值范围.3)三角形PCQ与三角形QMA能相似吗?若能

已知:RT三角形ABC中,∠C=90°,AC=4,cotB=根号3,MN=2,QM垂直于AB,PN平行于QM,设AM=x,MNPO的面积为y1) 当X=5/6时,球PB的长2)求y关于x 的函数解析式,并写出X的取值范围.3)三角形PCQ与三角形QMA能相似吗?若能
已知:RT三角形ABC中,∠C=90°,AC=4,cotB=根号3,MN=2,QM垂直于AB,PN平行于QM,设AM=x,MNPO的面积为y
1) 当X=5/6时,球PB的长
2)求y关于x 的函数解析式,并写出X的取值范围.
3)三角形PCQ与三角形QMA能相似吗?若能,请写出X的值,若不能,请说明理由
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已知:RT三角形ABC中,∠C=90°,AC=4,cotB=根号3,MN=2,QM垂直于AB,PN平行于QM,设AM=x,MNPO的面积为y1) 当X=5/6时,球PB的长2)求y关于x 的函数解析式,并写出X的取值范围.3)三角形PCQ与三角形QMA能相似吗?若能
第一问,cotB=根3,所以B=30°,所以AB=AC/sin30°=8,所以BN=AB-AN=31/6,所以PB=BN/cos30,=31根3/9
第二问,QM=tan60X,PN=(8-X-2)tan30,所以带入梯形面积公式,y=2根3/3X+2根3,0≤X≤6
第三问,假设其相似,则Q一定在AC边上,所以∠A=∠CPQ=60°,所以AQ=2X,QC=4-2X,过Q作QE垂直PN,则MN=QE=2,且,∠PQE=30°,所以PQ=4/根3,所以由三角形相似,PQ/AQ=QC/QM,所以带入数据我自己随便算了下,两个X都是负值,应该不存在这样的X吧,具体应该是这样写,答案你在自己算算吧,我不确定~打字好麻烦,打了好长时间呢~

cotB=根3,所以B=30°,所以AB=AC/sin30°=8,所以BN=AB-AN=31/6,所以PB=BN/cos30,=31根3/9
QM=tan60X,PN=(8-X-2)tan30,所以带入梯形面积公式,y=2根3/3X+2根3,0≤X≤6
假设其相似,则Q一定在AC边上,所以∠A=∠CPQ=60°,所以AQ=2X,QC=4-2X,过Q作QE垂直PN,则MN=QE=2,...

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cotB=根3,所以B=30°,所以AB=AC/sin30°=8,所以BN=AB-AN=31/6,所以PB=BN/cos30,=31根3/9
QM=tan60X,PN=(8-X-2)tan30,所以带入梯形面积公式,y=2根3/3X+2根3,0≤X≤6
假设其相似,则Q一定在AC边上,所以∠A=∠CPQ=60°,所以AQ=2X,QC=4-2X,过Q作QE垂直PN,则MN=QE=2,且,∠PQE=30°,所以PQ=4/根3,所以由三角形相似,PQ/AQ=QC/QM
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已知,Rt三角形ABC中,∠C=90°,若a+b=14cm,c=10.则RT三角形的面积为 已知rt△abc中,∠c=90°,tanb=12/5,且它的周长为60,则此rt三角形abc的面积是 已知:Rt△ABC中,∠C=90°,∠A=45°,Rt△关于AB所在直线成轴对称的三角形为Rt△ABC',则△CAC'为__三角形 已知在RT△ABC中∠c=90°若a+b=13、c-9求三角形ABC 的面积 在Rt三角形abc中,∠C=90°,已知sinA=sinB,试求∠A的读数RT!...急..这是我们今天晚上作业... 已知tanB=2分之3,b=9,求a,c.RT三角形ABC中,C=90° 已知在Rt三角形ABC中,∠C=90°,a:b=3:4,且Rt三角形ABC的周长为60,求三边的长如图,在rt三角形ABC中,∠C=90°,BC=12cm,S△ABC=30cm²,求AB的长. Rt三角形ABC中,∠C=90°,a+b=8,c=6,求Rt三角形ABC的面积 如图所示,在RT△ABC中,∠ABC=90°,将RT△ABC绕点C顺时针方向如图所示,在RT三角形ABC中,角ABC等于90度,将RT三角形ABC绕点C顺时针方向旋转60度得到三角形DEC,点E在AC上,再将RT三角形沿着所在的直线翻 RT三角形ABC中,∠C=90°,sinA=1/2,则∠A? 已知RT三角形ABC中,角C等于90度,若a+b=14cm,c=10cm,则RT三角形ABC面积是 RT三角形ABC中,∠C=90°,已知a=根号3,∠A=60°,求b、c 在RT三角形ABC中,∠C=90度,已知tanB=根号5/2,则cosA= 在rt三角形ABC中,∠C=90°,已知a=6,b=2根号3,求∠B,c 在rt三角形abc中 角c 90度 已知b=15,∠A=30°,则a=,c= 在Rt三角形adc中,∠C=90°已知a:b=3:4,c=10 则△ABC=? 已知Rt三角形ABC中,∠C=90,AC=4cm,BC=3cm.先将三角形ABC进行折叠,使顶点A、B 解关于三角形的面积的数学题已知Rt三角形ABC中,角C=90°,若a+b=14cm,c=10cm,求Rt三角形ABC的面积.