已知xy互为相反数,且(2x-3)²-(2y+1)²=48,求xy的值
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![已知xy互为相反数,且(2x-3)²-(2y+1)²=48,求xy的值](/uploads/image/z/14998235-59-5.jpg?t=%E5%B7%B2%E7%9F%A5xy%E4%BA%92%E4%B8%BA%E7%9B%B8%E5%8F%8D%E6%95%B0%2C%E4%B8%94%282x-3%29%26%23178%3B-%282y%2B1%EF%BC%89%26%23178%3B%3D48%2C%E6%B1%82xy%E7%9A%84%E5%80%BC)
已知xy互为相反数,且(2x-3)²-(2y+1)²=48,求xy的值
已知xy互为相反数,且(2x-3)²-(2y+1)²=48,求xy的值
已知xy互为相反数,且(2x-3)²-(2y+1)²=48,求xy的值
即x+y=0
y=-x
所以(2x-3)²-(-2x+1)²=48
4x²-12x+9-4x²+4x-1=48
8x=-40
x=-5
y=5
所以xy=-25