解下列一元二次方程,全都要用因式分解法计算.(1)X(X—2)+X—2=0 (2)Y(Y—2)=2Y (3)3(X—5)² =2(5—X)(4)(X—3)(X+1)=5(5)(3X—2)(3X+2)=12 (注:大写字母是未知数,
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![解下列一元二次方程,全都要用因式分解法计算.(1)X(X—2)+X—2=0 (2)Y(Y—2)=2Y (3)3(X—5)² =2(5—X)(4)(X—3)(X+1)=5(5)(3X—2)(3X+2)=12 (注:大写字母是未知数,](/uploads/image/z/15210091-19-1.jpg?t=%E8%A7%A3%E4%B8%8B%E5%88%97%E4%B8%80%E5%85%83%E4%BA%8C%E6%AC%A1%E6%96%B9%E7%A8%8B%2C%E5%85%A8%E9%83%BD%E8%A6%81%E7%94%A8%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3%E6%B3%95%E8%AE%A1%E7%AE%97.%EF%BC%881%EF%BC%89X%EF%BC%88X%E2%80%942%EF%BC%89%2BX%E2%80%942%3D0+%EF%BC%882%EF%BC%89Y%EF%BC%88Y%E2%80%942%EF%BC%89%3D2Y+%EF%BC%883%EF%BC%893%EF%BC%88X%E2%80%945%EF%BC%89%26%23178%3B+%3D2%EF%BC%885%E2%80%94X%EF%BC%89%EF%BC%884%EF%BC%89%EF%BC%88X%E2%80%943%EF%BC%89%EF%BC%88X%2B1%EF%BC%89%3D5%EF%BC%885%EF%BC%89%EF%BC%883X%E2%80%942%EF%BC%89%EF%BC%883X%2B2%EF%BC%89%3D12+%EF%BC%88%E6%B3%A8%EF%BC%9A%E5%A4%A7%E5%86%99%E5%AD%97%E6%AF%8D%E6%98%AF%E6%9C%AA%E7%9F%A5%E6%95%B0%2C)
解下列一元二次方程,全都要用因式分解法计算.(1)X(X—2)+X—2=0 (2)Y(Y—2)=2Y (3)3(X—5)² =2(5—X)(4)(X—3)(X+1)=5(5)(3X—2)(3X+2)=12 (注:大写字母是未知数,
解下列一元二次方程,全都要用因式分解法计算.
(1)X(X—2)+X—2=0 (2)Y(Y—2)=2Y (3)3(X—5)² =2(5—X)(4)(X—3)(X+1)=5
(5)(3X—2)(3X+2)=12 (注:大写字母是未知数,
解下列一元二次方程,全都要用因式分解法计算.(1)X(X—2)+X—2=0 (2)Y(Y—2)=2Y (3)3(X—5)² =2(5—X)(4)(X—3)(X+1)=5(5)(3X—2)(3X+2)=12 (注:大写字母是未知数,
1、(x-2)(x+1)=0
∴x=2 x=-1
2、y(y-2)-2y=0
y(y-4)=0
∴y=0 y=4
3、3(x-5)²+2(x-5)=0
(x-5)(3x-15+2)=0
(x-5)(3x-13)=0
∴x=5 x=13/3
4、x²-2x-3=5
x²-2x-8=0
(x-4)(x+2)=0
x=4 x=-2
5、9x²-4=12
9x²-16=0
(3x+4)(3x-4)=0
x=-4/3 x=4/3
(x+1)(x-2)=0
y(y-4)=0
(x-5+√2)(x-5-√2)=0
(x+2)(x-4)=0
(3x+4)(3x-4)=0