圆Cx=4cosA,y=4sinA (A为参数),直线l:x=2t,y=2+根号3t(t为参数)设L和C相交于A,B两点求:|PA|*|PB||PA|+|PB||AB|1/|PA|+1/|PB|
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![圆Cx=4cosA,y=4sinA (A为参数),直线l:x=2t,y=2+根号3t(t为参数)设L和C相交于A,B两点求:|PA|*|PB||PA|+|PB||AB|1/|PA|+1/|PB|](/uploads/image/z/1534794-42-4.jpg?t=%E5%9C%86Cx%3D4cosA%2Cy%3D4sinA+%28A%E4%B8%BA%E5%8F%82%E6%95%B0%29%2C%E7%9B%B4%E7%BA%BFl%3Ax%3D2t%2Cy%3D2%2B%E6%A0%B9%E5%8F%B73t%EF%BC%88t%E4%B8%BA%E5%8F%82%E6%95%B0%EF%BC%89%E8%AE%BEL%E5%92%8CC%E7%9B%B8%E4%BA%A4%E4%BA%8EA%2CB%E4%B8%A4%E7%82%B9%E6%B1%82%EF%BC%9A%7CPA%7C%2A%7CPB%7C%7CPA%7C%2B%7CPB%7C%7CAB%7C1%2F%7CPA%7C%2B1%2F%7CPB%7C)
圆Cx=4cosA,y=4sinA (A为参数),直线l:x=2t,y=2+根号3t(t为参数)设L和C相交于A,B两点求:|PA|*|PB||PA|+|PB||AB|1/|PA|+1/|PB|
圆Cx=4cosA,y=4sinA (A为参数),直线l:x=2t,y=2+根号3t(t为参数)
设L和C相交于A,B两点
求:
|PA|*|PB|
|PA|+|PB|
|AB|
1/|PA|+1/|PB|
圆Cx=4cosA,y=4sinA (A为参数),直线l:x=2t,y=2+根号3t(t为参数)设L和C相交于A,B两点求:|PA|*|PB||PA|+|PB||AB|1/|PA|+1/|PB|
这题应该是有思路的,请问哪里来的P点.
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