根号2/2cos(2x+π/4)+sin^2 x 求化简过程根号2/2cos(2x+π/4)+sin^2 x=1/2cos2x-1/2sin2x+1/2(1-cos2x)=1/2-1/2sin2x 求化简过程,谢谢
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![根号2/2cos(2x+π/4)+sin^2 x 求化简过程根号2/2cos(2x+π/4)+sin^2 x=1/2cos2x-1/2sin2x+1/2(1-cos2x)=1/2-1/2sin2x 求化简过程,谢谢](/uploads/image/z/1535067-27-7.jpg?t=%E6%A0%B9%E5%8F%B72%2F2cos%282x%2B%CF%80%2F4%29%2Bsin%5E2+x+%E6%B1%82%E5%8C%96%E7%AE%80%E8%BF%87%E7%A8%8B%E6%A0%B9%E5%8F%B72%2F2cos%282x%2B%CF%80%2F4%EF%BC%89%2Bsin%5E2+x%3D1%2F2cos2x-1%2F2sin2x%2B1%2F2%281-cos2x%29%3D1%2F2-1%2F2sin2x+++%E6%B1%82%E5%8C%96%E7%AE%80%E8%BF%87%E7%A8%8B%2C%E8%B0%A2%E8%B0%A2)
根号2/2cos(2x+π/4)+sin^2 x 求化简过程根号2/2cos(2x+π/4)+sin^2 x=1/2cos2x-1/2sin2x+1/2(1-cos2x)=1/2-1/2sin2x 求化简过程,谢谢
根号2/2cos(2x+π/4)+sin^2 x 求化简过程
根号2/2cos(2x+π/4)+sin^2 x=1/2cos2x-1/2sin2x+1/2(1-cos2x)=1/2-1/2sin2x 求化简过程,谢谢
根号2/2cos(2x+π/4)+sin^2 x 求化简过程根号2/2cos(2x+π/4)+sin^2 x=1/2cos2x-1/2sin2x+1/2(1-cos2x)=1/2-1/2sin2x 求化简过程,谢谢
cos(2x+π/4)=cosπ/4cos2x-sinπ/4sin2x
cosπ/4=sinπ/4=2分之根号2
cos2x=cosx^2-sinx^2=1-2sinx^2
sinx^2=(1-cos2x)/2
化简2sin^2[(π/4)+x]+根号3(sin^x-cos^x)-1
根号下2/4sin(π/4-x)+根号下6/4cos(π/4-x)
f(x)=2sin^2(π/4+x)+根号3(sin^2x+cos^2x)f(x)=2sin^2(π/4+x)+根号3(sin^2x-cos^2x) 符号打错了
f(x)=2sinπ/4cosπ/4- 2根号3sin^2π/4+根号3
f(x)=2sinπ/4cosπ/4-2根号3sin^2π/4+根号3
(1)化简:根号2sin(π/4-x)+根号6cos(π/4-x)(2)sin(67°-x)cos(x-22°)+cos(67°-x)cos(112°-x)的值为
化简:根号2sin(π/4-x)+根号6cos(π/4-x)(2)sin(67°-x)cos(x-22°)+cos(67°-x)cos(112°-x)的值为
Sin(x/2)+cos(x/2)为什么等于根号2倍sin(x/2+派/4)?
化简 1/2cos x-根号3/2sin x 根3sin x+cos x
sin 2x+cos 2x=根号2sin (2x+π/4)怎么得出来的,
化简sin(x+π/2)分之1+根号二cos(2x-π/4)
1-cos^2x+sin2x怎么变成根号2sin[2X-π/4]+1
化简根号2sin(π/3-x)+根号6cos(π/3-x)
化简 1/2cos x-根号3/2sin x
化简:3/2cos x-(根号3)/2sin x
cos 2x +根号下3乘sin 2x
根号3 /2SIN X-1/2COS X
证明sin x+cos x的最大值等于 根号2