(2x+3)²-4(2x+3)+4=0 (x-3)²=(3x-2)²一元二次方程分解因式法怎么解过程
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(2x+3)²-4(2x+3)+4=0 (x-3)²=(3x-2)²一元二次方程分解因式法怎么解过程
(2x+3)²-4(2x+3)+4=0 (x-3)²=(3x-2)²一元二次方程分解因式法怎么解过程
(2x+3)²-4(2x+3)+4=0 (x-3)²=(3x-2)²一元二次方程分解因式法怎么解过程
(2x+3)²-4(2x+3)+4=0
[(2x+3)-2]^2=0
2x+3-2=0
2x=-1
x=-1/2.
(x-3)²=(3x-2)²
(x-3)^2-(3x-2)^2=0
(x-3+3x-2)(x-3-3x+2)=0
(4x-5)(-2x-1)=0
x1=5/4
x2=-1/2
(2x+3)²-4(2x+3)+4=0
[(2x+3)-2]²=0
(2x+3)-2=0
2x+1=0
2x=-1
∴x1=x2=-½
(x-3)²=(3x-2)²
(x-3)²-(3x-2)²=0
[(x-3)+(3x-2)][(x-3)-(3x-2)]=0
(4x-5)(-2x-1)=0
4x-5=0或-2x-1=0
∴x1=5/4, x2=-½
(2x+3)^2-4(2x+3)+4=0
(2x+3-2)^2=0
2x+1=0
x=-1/2
(x-3)^2=(3x-2)^2
x^2-6x+9=9x^2-12x+4
8x^2-6x-5=0
(2x+1)(4x-5)=0
2x+1=0或4x-5=0
x=-1/2或x=5/4
(2x+3)²-4(2x+3)+4=0
(2x+3-2)的平方=0
x1=x2=-1/2
(x-3)²=(3x-2)²
(x-3)²-(3x-2)²=0
(x-3+3x-2)(x-3-3x+2)=0
(4x-5)(-2x-1)=0
x1=5/4
x2=-1/2