若x²-x-2=0,则x²-2+2√3除以(x²-x)²-1+√3的值等于
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![若x²-x-2=0,则x²-2+2√3除以(x²-x)²-1+√3的值等于](/uploads/image/z/1629465-33-5.jpg?t=%E8%8B%A5x%26%23178%3B-x-2%3D0%2C%E5%88%99x%26%23178%3B-2%2B2%E2%88%9A3%E9%99%A4%E4%BB%A5%28x%26%23178%3B-x%29%26%23178%3B-1%2B%E2%88%9A3%E7%9A%84%E5%80%BC%E7%AD%89%E4%BA%8E)
若x²-x-2=0,则x²-2+2√3除以(x²-x)²-1+√3的值等于
若x²-x-2=0,则x²-2+2√3除以(x²-x)²-1+√3的值等于
若x²-x-2=0,则x²-2+2√3除以(x²-x)²-1+√3的值等于
x²-x-2=0
x²-x=2
所以原式=(2+2√3)/(2²-1+√3)=(2+2√3)/(3+√3)
=(2+2√3)(3-√3)/(3+√3)(3-√3)
=(6-2√3+6√3-6)/(9-3)
=4√3/6
=2√3/3