(2x^3y)^2×(-2xy)+(-2x^3y)^3÷(2x^2)

来源：学生作业帮助网 编辑：作业帮 时间：2024/05/15 01:22:16
(2x^3y)^2×(-2xy)+(-2x^3y)^3÷(2x^2)

(2x^3y)^2×(-2xy)+(-2x^3y)^3÷(2x^2)
(2x^3y)^2×(-2xy)+(-2x^3y)^3÷(2x^2)

(2x^3y)^2×(-2xy)+(-2x^3y)^3÷(2x^2)
原式
=(2x^3y)^2×(-2xy)+(-2x^3y)^3÷(2x^2)
=(4x^6y^2)×(-2xy)+(-8x^9y^3)÷(2x^2)
=-8x^7y^3-4x^7y^3
=-12x^7y^3

(2x^3y)^2×(-2xy)+(-2x^3y)^3÷(2x^2)
=(4x^6y²)×(-2xy)+(-8x^9y³)÷(2x²)
=-8x^7y³-4x^7y³
=-12x^7y³

=4x^6y^2×(-2xy) -8x^9y^3÷2x^2
=-8x^7y^3-4x^7y^3
=-12x^7y^3

2x²y-3(2xy-xy)-xy x^2-xy-6y^2+3xy+y+2 因式分解:12xy^2(y-x)+xy^3(x-y)+4x^2y(x-y) X^Y-2XY^2+y^3 化简：3x^2-[5xy-(x^y-3xy)+4x^2y-8xy] xy-2{xy-[3x^2y-(4xy^2+0.5xy)]+4x^2y}+6xy^2 （X-3xy+4xy-y）-[-2x-2（xy-3/2xy）-y]+6xy的过程 计算：3xy[2xy-x（y-2）+x] 计算3xy[2xy-x(y-2)+x-1] （-3x^y+2xy)-( )=4x^+xy x*x+xy=3,xy+y*y=2,则x*x+2xy+y*y=________? x^2-xy/xy-y^2约分 (x-2xy)*(-xy+2y*y)-(3x*x-2xy)(x-9xy+6y*y)答案应为-2x-x*x-3x， （x^2+xy/x-y)/（xy/x-y)计算 因式分解 x-xy+3y-3x 2x+xy-y-4x+5y-6 3xy(x^2y-xy^2+xy)-xy^2(2x^2-6xy+2x)过程 (-1/3xy)^2•[xy(2x-y)-2x(xy-y^2)] 计算题 xy【y^2+x^2】-y^2【xy+2x】-3xy