当h=多少时,多项式3X ²-2kxy-3y ²+5分之1xy+7y²中不含xy项
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![当h=多少时,多项式3X ²-2kxy-3y ²+5分之1xy+7y²中不含xy项](/uploads/image/z/1664763-51-3.jpg?t=%E5%BD%93h%3D%E5%A4%9A%E5%B0%91%E6%97%B6%2C%E5%A4%9A%E9%A1%B9%E5%BC%8F3X+%26%23178%3B-2kxy-3y+%26%23178%3B%2B5%E5%88%86%E4%B9%8B1xy%2B7y%26%23178%3B%E4%B8%AD%E4%B8%8D%E5%90%ABxy%E9%A1%B9)
当h=多少时,多项式3X ²-2kxy-3y ²+5分之1xy+7y²中不含xy项
当h=多少时,多项式3X ²-2kxy-3y ²+5分之1xy+7y²中不含xy项
当h=多少时,多项式3X ²-2kxy-3y ²+5分之1xy+7y²中不含xy项
答案:
要想使多项式中不存在xy项,只需要多项式中xy项的系数为0,
又题意可得方程:-2k+(1/5) = 0
解得:k = 1/10;