分式方程1.(3/x^2+2x)-(1/x^2-2x)=0 2.(x/x-3)=(x^1/x-1) 3.(x-3/x-2)+1=(3/2-x) 4.(2x+1/x^2+x)=(5/6x+6)5.3/2-1/3x-1=5/6x-2
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![分式方程1.(3/x^2+2x)-(1/x^2-2x)=0 2.(x/x-3)=(x^1/x-1) 3.(x-3/x-2)+1=(3/2-x) 4.(2x+1/x^2+x)=(5/6x+6)5.3/2-1/3x-1=5/6x-2](/uploads/image/z/168091-43-1.jpg?t=%E5%88%86%E5%BC%8F%E6%96%B9%E7%A8%8B1.%283%2Fx%5E2%2B2x%29-%281%2Fx%5E2-2x%29%3D0+2.%28x%2Fx-3%29%3D%28x%5E1%2Fx-1%29+3.%28x-3%2Fx-2%29%2B1%3D%283%2F2-x%29+4.%282x%2B1%2Fx%5E2%2Bx%29%3D%285%2F6x%2B6%295.3%2F2-1%2F3x-1%3D5%2F6x-2)
分式方程1.(3/x^2+2x)-(1/x^2-2x)=0 2.(x/x-3)=(x^1/x-1) 3.(x-3/x-2)+1=(3/2-x) 4.(2x+1/x^2+x)=(5/6x+6)5.3/2-1/3x-1=5/6x-2
分式方程1.(3/x^2+2x)-(1/x^2-2x)=0 2.(x/x-3)=(x^1/x-1) 3.(x-3/x-2)+1=(3/2-x) 4.(2x+1/x^2+x)=(5/6x+6)
5.3/2-1/3x-1=5/6x-2
分式方程1.(3/x^2+2x)-(1/x^2-2x)=0 2.(x/x-3)=(x^1/x-1) 3.(x-3/x-2)+1=(3/2-x) 4.(2x+1/x^2+x)=(5/6x+6)5.3/2-1/3x-1=5/6x-2
1.(3/x^2+2x)-(1/x^2-2x)=0 2.(x/x-3)=(x^1/x-1)
3/x^2+2x-1/x^2+2x=0 表示题目看不懂
2/x^2+4x=0
(2+4x^3)/x=0
2+4x^3=0
x=-1/2的三次根号
3.(x-3/x-2)+1=(3/2-x) 4.(2x+1/x^2+x)=(5/6x+6)
若题目没理解错就是:表示题目不明
(x-3)/(x-2)+1-3/(2-x)=0
(x-3)/(x-2)+1-3/(x-2)=0
x/(x-2)+1=0
(x+x-2)/(x-2)=0
x=1
他的答案看不明啊