tana=-1/2,求(1+2sinacosa)/(sin²a-cos²a)
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![tana=-1/2,求(1+2sinacosa)/(sin²a-cos²a)](/uploads/image/z/1802082-66-2.jpg?t=tana%EF%BC%9D-1%2F2%2C%E6%B1%82%281%2B2sinacosa%29%2F%28sin%26%23178%3Ba-cos%26%23178%3Ba%29)
tana=-1/2,求(1+2sinacosa)/(sin²a-cos²a)
tana=-1/2,求(1+2sinacosa)/(sin²a-cos²a)
tana=-1/2,求(1+2sinacosa)/(sin²a-cos²a)
tana=2求tan2a-tana/1+tan2atana
在三角形ABC中,S三角形ABC的值等于?A 1/2 ab cosAB 1/2 ab sinAC 1/2 a sinB*sinCD 1/2 ab sinC
根号[1+cosa/1-cosa]+根号[1-cosa/1+cosa]……A.2/sinaB.-2/sinaC.2/|sina|D.-2/|cosa|
(1+tanA)/(1-tanA)=2,求sinAcosA=
已知1/tana+tana=2求sina+cosa
已知1/tana+tana=2求sinacosa
已知tana=2,求tan2a-tana/1+tan2a·tana的值
-2tana+3sinb+5=0 tana-6sinb-1=0 求tana
(2tana/2)/[1+(tana/2)^2]为什么=tana
(cota/2-tana/2)(1+tana tana/2)可化简为
tan2a=2tana/[1-(tana)^2
求证tanA-1/tanA=-(2/tan2A)
化简sin2a(1+tana*tana/2)
化简 tanA-1/tanA+2/tan2A
tana=1/2,求sinacosa
tanA=1/2,求角A
已知tana=2,求1/sinacosa
tanA=2,求1/(sin2A)