【求解一道高次方程!a×(1/9a³﹣1/3a²+5/4a)=9/4求a的值!
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【求解一道高次方程!a×(1/9a³﹣1/3a²+5/4a)=9/4求a的值!
【求解一道高次方程!
a×(1/9a³﹣1/3a²+5/4a)=9/4
求a的值!
【求解一道高次方程!a×(1/9a³﹣1/3a²+5/4a)=9/4求a的值!
a(4a^3-12a^2+45a)=81
4a^4-12a^3+45a^2-81=0
4a^4-6a^3-6a^3+9a^2+36a^2-54a+54a-81=0
(2a-3)(2a^3-3a^2+18a+27)=0
2a-3=0, 得:a1=3/2
2a^3-3a^2+18a+27=0,用公式得:
a2=-1.12825766832628
a3=1.31412883416314-3.19975268979456i
a4=1.31412883416314+3.19975268979456i