在△ABC的三边,a,b,c满足a²+b²+c²+338=10a+24b+26c,判断△ABC的形状
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/23 14:31:22
![在△ABC的三边,a,b,c满足a²+b²+c²+338=10a+24b+26c,判断△ABC的形状](/uploads/image/z/1835533-37-3.jpg?t=%E5%9C%A8%E2%96%B3ABC%E7%9A%84%E4%B8%89%E8%BE%B9%2Ca%2Cb%2Cc%E6%BB%A1%E8%B6%B3a%26%23178%3B%2Bb%26%23178%3B%2Bc%26%23178%3B%2B338%3D10a%2B24b%2B26c%2C%E5%88%A4%E6%96%AD%E2%96%B3ABC%E7%9A%84%E5%BD%A2%E7%8A%B6)
在△ABC的三边,a,b,c满足a²+b²+c²+338=10a+24b+26c,判断△ABC的形状
在△ABC的三边,a,b,c满足a²+b²+c²+338=10a+24b+26c,判断△ABC的形状
在△ABC的三边,a,b,c满足a²+b²+c²+338=10a+24b+26c,判断△ABC的形状
a²+b²+c²+338=10a+24b+26c,
∴(a-5)²+(b-12)²+(c-13)²=0
∴a=5,b=12,c=13.a²+b²=c²
∴△ABC是直角三角形.