a=2-√2,b=2+√2,求(a³b+a²b²/a²+2ab+b²)÷(a²-ab/a²-b²)
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a=2-√2,b=2+√2,求(a³b+a²b²/a²+2ab+b²)÷(a²-ab/a²-b²)
a=2-√2,b=2+√2,求(a³b+a²b²/a²+2ab+b²)÷(a²-ab/a²-b²)
a=2-√2,b=2+√2,求(a³b+a²b²/a²+2ab+b²)÷(a²-ab/a²-b²)
(a³b+a²b²/a²+2ab+b²)÷(a²-ab/a²-b²)
=【a²b(a+b)/(a+b)²】/【a(a-b)/((a+b)(a-b))】
=a²b/(a+b)*(a+b)/a
=ab
=(2-√2)*(2+√2)
=2²-2
=2
【欢迎追问,】
(a³b+a²b²)/(a²+2ab+b²)÷[(a²-ab)/(a²-b²)]
=a²b(a+b)/(a+b)²÷[a(a-b)/(a-b)(a+b)]
=a²b/(a+b)÷[a/(a+b)]
=a²b/(a+b)*(a+b)/a
=b