若a-1的绝对值+(b-2)²=0,A=3a²-6ab+b²,B= -a²-5,求A-B的值
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若a-1的绝对值+(b-2)²=0,A=3a²-6ab+b²,B= -a²-5,求A-B的值
若a-1的绝对值+(b-2)²=0,A=3a²-6ab+b²,B= -a²-5,求A-B的值
若a-1的绝对值+(b-2)²=0,A=3a²-6ab+b²,B= -a²-5,求A-B的值
若a-1的绝对值+(b-2)²=0,
|a-1| +(b-2)² =0
因为两个整式都大于等于0,相加等于0就是都等于0
a=1,b=2
A=3a²-6ab+b²,
=3-12+4
=-6
B= -a²-5,
=-6
求A-B的值
A-B=0
无疑问,
a=1 b=2
A-B=3a²-6ab+b²+a²+5
=4a²-6ab+b²+5
=4-12+4+5
=1