求解初二数学下册计算(1-x²/x²+4x+4)÷(x-1)²×(x²+3x+2/x-1)计算:(1-x²/x²+4x+4)÷(x-1)²×(x²+3x+2/x-1)
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![求解初二数学下册计算(1-x²/x²+4x+4)÷(x-1)²×(x²+3x+2/x-1)计算:(1-x²/x²+4x+4)÷(x-1)²×(x²+3x+2/x-1)](/uploads/image/z/2538654-6-4.jpg?t=%E6%B1%82%E8%A7%A3%E5%88%9D%E4%BA%8C%E6%95%B0%E5%AD%A6%E4%B8%8B%E5%86%8C%E8%AE%A1%E7%AE%97%281-x%26%23178%3B%2Fx%26%23178%3B%2B4x%2B4%29%C3%B7%28x-1%29%26%23178%3B%C3%97%EF%BC%88x%26%23178%3B%2B3x%2B2%2Fx-1%EF%BC%89%E8%AE%A1%E7%AE%97%EF%BC%9A%281-x%26%23178%3B%2Fx%26%23178%3B%2B4x%2B4%29%C3%B7%28x-1%29%26%23178%3B%C3%97%EF%BC%88x%26%23178%3B%2B3x%2B2%2Fx-1%EF%BC%89)
求解初二数学下册计算(1-x²/x²+4x+4)÷(x-1)²×(x²+3x+2/x-1)计算:(1-x²/x²+4x+4)÷(x-1)²×(x²+3x+2/x-1)
求解初二数学下册计算(1-x²/x²+4x+4)÷(x-1)²×(x²+3x+2/x-1)
计算:(1-x²/x²+4x+4)÷(x-1)²×(x²+3x+2/x-1)
求解初二数学下册计算(1-x²/x²+4x+4)÷(x-1)²×(x²+3x+2/x-1)计算:(1-x²/x²+4x+4)÷(x-1)²×(x²+3x+2/x-1)
(1-x²/x²+4x+4)÷(x-1)²×(x²+3x+2/x-1)
=(1+x)(1-x)/(x+2)的平方 X 1/(x-1)的平方 X (x+2)(x+1)/(x-1)
=(x+1)的平方/-(x+2)(x-1)的平方
原式=[1-x^2/(x+2)^2]/(x-1)^2*[(x+1)(x+2)/(x-1)]
=2*(2x+2)/[(x-1)^2(x+2)^2]*[(x+1)(x+2)/(x-1)]
=4*(x+1)^2/[(x-1)^3(x+2)]
(1-x²/x²+4x+4)÷(x-1)²×(x²+3x+2/x-1)
=[(1-x)²/(x²+4x+4)] ÷ (x-1)² × [ (x²+3x+2)/(x-1)]
=[(1-x)(x+1) / (x+2)² ] ÷ (x-1)(x+1)(x+2)
=[ -1/(x+2)² ] ÷ (x+2)
=[ -1 / (x+2)² ] × 1/(x+2)
=-1 / (x+2)³