已知a+x²=2008,b+x²=2009,c+x²=2010,且abc=3求a/bc+c/ab+b/ac-1/a-1/b-1/c的值
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![已知a+x²=2008,b+x²=2009,c+x²=2010,且abc=3求a/bc+c/ab+b/ac-1/a-1/b-1/c的值](/uploads/image/z/2608714-10-4.jpg?t=%E5%B7%B2%E7%9F%A5a%2Bx%26%23178%3B%3D2008%2Cb%2Bx%26%23178%3B%3D2009%2Cc%2Bx%26%23178%3B%3D2010%2C%E4%B8%94abc%3D3%E6%B1%82a%2Fbc%2Bc%2Fab%2Bb%2Fac-1%2Fa-1%2Fb-1%2Fc%E7%9A%84%E5%80%BC)
已知a+x²=2008,b+x²=2009,c+x²=2010,且abc=3求a/bc+c/ab+b/ac-1/a-1/b-1/c的值
已知a+x²=2008,b+x²=2009,c+x²=2010,且abc=3
求a/bc+c/ab+b/ac-1/a-1/b-1/c的值
已知a+x²=2008,b+x²=2009,c+x²=2010,且abc=3求a/bc+c/ab+b/ac-1/a-1/b-1/c的值
a-b=-1,b-c=-1,c-a=2
所以原式=(a²+b²+c²-ab-bc-ac)/abc
=(2a²+2b²+2c²-2ab-2bc-2ac)/2abc=
=[(a²-2ab+b²)+(b²-2bc+c²)+(c²-2ac+a²)]/2abc
=[(a-b)²+(b-c)²+(c-a)²]/2abc
=1