设数列{An}的前n项和为Sn=2n^2,{bn}为等比数列,且a1=b1,b2(a2-a1)=b1.求数列{An}和{bn}的通项公式
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![设数列{An}的前n项和为Sn=2n^2,{bn}为等比数列,且a1=b1,b2(a2-a1)=b1.求数列{An}和{bn}的通项公式](/uploads/image/z/2702547-27-7.jpg?t=%E8%AE%BE%E6%95%B0%E5%88%97%7BAn%7D%E7%9A%84%E5%89%8Dn%E9%A1%B9%E5%92%8C%E4%B8%BASn%3D2n%5E2%2C%7Bbn%7D%E4%B8%BA%E7%AD%89%E6%AF%94%E6%95%B0%E5%88%97%2C%E4%B8%94a1%3Db1%2Cb2%28a2-a1%29%3Db1.%E6%B1%82%E6%95%B0%E5%88%97%7BAn%7D%E5%92%8C%7Bbn%7D%E7%9A%84%E9%80%9A%E9%A1%B9%E5%85%AC%E5%BC%8F)
设数列{An}的前n项和为Sn=2n^2,{bn}为等比数列,且a1=b1,b2(a2-a1)=b1.求数列{An}和{bn}的通项公式
设数列{An}的前n项和为Sn=2n^2,{bn}为等比数列,且a1=b1,b2(a2-a1)=b1.求数列{An}和{bn}的通项公式
设数列{An}的前n项和为Sn=2n^2,{bn}为等比数列,且a1=b1,b2(a2-a1)=b1.求数列{An}和{bn}的通项公式
an=Sn-Sn-1=4n-2(n大于等于2)
又a1=s1=2
所欲an=4n-2
B1=2 b2/b1=1/a2-a1=1/4
所以bn=2^(3-2n)
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