若x²+2x+y²-4y+5=0,则x= ,y= .已知X+Y=-2,XY=-3,求下列各式的值.(1)x²y+xy² (2)(x-y)²要具体过程,
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![若x²+2x+y²-4y+5=0,则x= ,y= .已知X+Y=-2,XY=-3,求下列各式的值.(1)x²y+xy² (2)(x-y)²要具体过程,](/uploads/image/z/2734949-29-9.jpg?t=%E8%8B%A5x%26%23178%3B%2B2x%2By%26%23178%3B-4y%2B5%3D0%2C%E5%88%99x%3D+%2Cy%3D+.%E5%B7%B2%E7%9F%A5X%2BY%3D-2%2CXY%3D-3%2C%E6%B1%82%E4%B8%8B%E5%88%97%E5%90%84%E5%BC%8F%E7%9A%84%E5%80%BC.%281%29x%26%23178%3By%2Bxy%26%23178%3B+%EF%BC%882%EF%BC%89%EF%BC%88x-y%29%26%23178%3B%E8%A6%81%E5%85%B7%E4%BD%93%E8%BF%87%E7%A8%8B%2C)
若x²+2x+y²-4y+5=0,则x= ,y= .已知X+Y=-2,XY=-3,求下列各式的值.(1)x²y+xy² (2)(x-y)²要具体过程,
若x²+2x+y²-4y+5=0,则x= ,y= .
已知X+Y=-2,XY=-3,求下列各式的值.(1)x²y+xy² (2)(x-y)²
要具体过程,
若x²+2x+y²-4y+5=0,则x= ,y= .已知X+Y=-2,XY=-3,求下列各式的值.(1)x²y+xy² (2)(x-y)²要具体过程,
x2y+xy2=xy(x+y)=(-3)*(-2)=6
(x-y)2=x2-2xy+y2=x2+2xy+y2-4xy=(x+y)2-4xy=4+12=16
(1)原式=xy(x+y)=-3x(-2)=6
(2)(x+y)²=x²+y²+2xy=4
x²+y²=4-2×(-3)=10
原式=x²+y²-2xy=10-2×(-3)=16第二题是(x-y)²吧,还有漏了
若x²+2x+y²-4y+5=0,则x= ,y= .无解...
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(1)原式=xy(x+y)=-3x(-2)=6
(2)(x+y)²=x²+y²+2xy=4
x²+y²=4-2×(-3)=10
原式=x²+y²-2xy=10-2×(-3)=16
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化简(x+1)²+(y-2)²=0 x=-1, y=2