..4道方程题a(x-1)=2xa²y²+y²=a(x²-x)²-4x²+4x-12=05(x-a)=ax+b
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![..4道方程题a(x-1)=2xa²y²+y²=a(x²-x)²-4x²+4x-12=05(x-a)=ax+b](/uploads/image/z/2832009-33-9.jpg?t=..4%E9%81%93%E6%96%B9%E7%A8%8B%E9%A2%98a%28x-1%29%3D2xa%26%23178%3By%26%23178%3B%2By%26%23178%3B%3Da%28x%26%23178%3B-x%29%26%23178%3B-4x%26%23178%3B%2B4x-12%3D05%28x-a%29%3Dax%2Bb)
..4道方程题a(x-1)=2xa²y²+y²=a(x²-x)²-4x²+4x-12=05(x-a)=ax+b
..4道方程题
a(x-1)=2x
a²y²+y²=a
(x²-x)²-4x²+4x-12=0
5(x-a)=ax+b
..4道方程题a(x-1)=2xa²y²+y²=a(x²-x)²-4x²+4x-12=05(x-a)=ax+b
a(x-1)=2x
ax-a=2x
(a-2)x=a
x=a/(a-2)
a²y²+y²=a
(a^2+1)y^2=a
y=±√[a/(a^2+1)]
(x²-x)²-4x²+4x-12=0
(x^2-x)^2-4(x^2-x)+2^2-16=0
[(x^2-x)-2]^2=16
x^2-x-2=±4
则x^2-x-6=0或x^2-x+2=0
x^2-x+2=0无实数解
x^2-x-6=0的解为:x1=3,x2=-2
5(x-a)=ax+b
5x-5a=ax+b
(5-a)x=5a+b
x=(5a+b)/(5-a)