已知z属于C,z的模=根号21,arg(z-4)=三分之派.求z
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![已知z属于C,z的模=根号21,arg(z-4)=三分之派.求z](/uploads/image/z/2906293-13-3.jpg?t=%E5%B7%B2%E7%9F%A5z%E5%B1%9E%E4%BA%8EC%2Cz%E7%9A%84%E6%A8%A1%3D%E6%A0%B9%E5%8F%B721%2Carg%28z-4%29%3D%E4%B8%89%E5%88%86%E4%B9%8B%E6%B4%BE.%E6%B1%82z)
已知z属于C,z的模=根号21,arg(z-4)=三分之派.求z
已知z属于C,z的模=根号21,arg(z-4)=三分之派.求z
已知z属于C,z的模=根号21,arg(z-4)=三分之派.求z
设z-4=r(cos60°+isin60°),则z=4+(1/2)r+[(√3/2)r]i,利用|z|=√21,代入计算出r=1或r=-5(舍去),从而z=9/2+√3/2i.
设 z= a+bi
tan(a-4) = b / (a-4) = 根号3
a^2 + b^2 = 21
a1= 9/2, a2 = 3/2
b1 = 根号3/2, b2 = -5根号3/2
z = 9/2 +根号3/2 i
或
z= 3/2 -5根号3/2 i
答案是9/2+(根号3)/2i?
画图....勾股定理求边....辐角弦值....z= r*(cosθ + i sinθ) .r是z的模,即:r = |z|; θ是z的辐角。
代入算....应该是那个答案吧....