因式分解题,拆添项,换元,第一题:x³-3x+2第二题:x³-48x+7第三题:x³-5x²+5x-4第四题:x(x+1)(x+2)(x+3)+1第五题:(xy-1)²+(xy-2)(x+y-2xy)

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因式分解题,拆添项,换元,第一题:x³-3x+2第二题:x³-48x+7第三题:x³-5x²+5x-4第四题:x(x+1)(x+2)(x+3)+1第五题:(xy-1)²+(xy-2)(x+y-2xy)

因式分解题,拆添项,换元,第一题:x³-3x+2第二题:x³-48x+7第三题:x³-5x²+5x-4第四题:x(x+1)(x+2)(x+3)+1第五题:(xy-1)²+(xy-2)(x+y-2xy)
因式分解题,拆添项,换元,
第一题:x³-3x+2
第二题:x³-48x+7
第三题:x³-5x²+5x-4
第四题:x(x+1)(x+2)(x+3)+1
第五题:(xy-1)²+(xy-2)(x+y-2xy)

因式分解题,拆添项,换元,第一题:x³-3x+2第二题:x³-48x+7第三题:x³-5x²+5x-4第四题:x(x+1)(x+2)(x+3)+1第五题:(xy-1)²+(xy-2)(x+y-2xy)
1,x³-3x+2=(x-1)(x²+x-2)
2,x³-48x+7
=x³-49x+x+7
=x(x-7)(x+7)+x+7
=(x²-7x+1)(x+7)
3,x³-5x²+5x-4
=(x³-4x²)-x²+5x-4
=x²(x-4)-(x-4)(x-1)
=(x-4)(x²-x+1)
4,x(x+1)(x+2)(x+3)+1
=(x²+x)(x²+5x+6)+1
=x^4(四次方)+6x³+11x²+1
=(x+3x+1)^2
5,这题是不是打疏忽了?
原题应为(xy-1)²+(x+y-2)(x+y-2xy) 不然无法分解
(x+y-2xy)(x+y-2)+(xy-1)2
=(y2-2y+1)x2-2(y2-2y+1)x+y2-2y+1
=(y-1)2(x-1)2
(跟在后的2为平方)

(1)x³-3x+2
=x³-1-3x+3
=(x³-1)-3(x-1)
=(x-1)(x²+x+1)-3(x-1)
=(x-1)(x²+x+1-3)
=(x-1)(x²+x-2)
=(x-1)(x-1)(x+2)

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(1)x³-3x+2
=x³-1-3x+3
=(x³-1)-3(x-1)
=(x-1)(x²+x+1)-3(x-1)
=(x-1)(x²+x+1-3)
=(x-1)(x²+x-2)
=(x-1)(x-1)(x+2)
=(x-1)²(x-2)
(2)x³-48x+7
临时有事要下了,如果明天问题还在我就继续回答吧
bye

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1.=(x^2-2x)-(x-2)
=(x-1)(x-2)
2.=(x^3-7x^2)+(7x^2-49x)+(x-7)
=(x-7)(x^2+7x+1)
3.=(x^3-4x^2)-(x^2-4x)+(x-4)
=(x-4)(x^2-x+1)
4.=(x^2+3x)(x^2+3x+2)+1
=(x^2+3x+1)-1)(x^2+...

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1.=(x^2-2x)-(x-2)
=(x-1)(x-2)
2.=(x^3-7x^2)+(7x^2-49x)+(x-7)
=(x-7)(x^2+7x+1)
3.=(x^3-4x^2)-(x^2-4x)+(x-4)
=(x-4)(x^2-x+1)
4.=(x^2+3x)(x^2+3x+2)+1
=(x^2+3x+1)-1)(x^2+3x+1+1)+1
=(x^2+3x+1)^2
5.=(xy-1)²+(xy-1-1)(x+y-2xy)
=(xy-1)²+(xy-1)(x+y-2xy)-(x+y-2xy)
=(xy-1)(x+y-xy-1)-(x+y-2xy)
= -(xy-1)(x-1)(y-1)-x(y-1)-y(x-1)
5不是很有思路

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1..(x^2-2x)-(x-2) =(x-1)(x-2)
2.

1.=(x^2-2x)-(x-2)
=(x-1)(x-2)
2.=(x^3-7x^2)+(7x^2-49x)+(x-7)
=(x-7)(x^2+7x+1)
3.=(x^3-4x^2)-(x^2-4x)+(x-4)
=(x-4)(x^2-x+1)
4.=(x^2+3x)(x^2+3x+2)+1
=(x^2+3x+1)-1)(x^2+...

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1.=(x^2-2x)-(x-2)
=(x-1)(x-2)
2.=(x^3-7x^2)+(7x^2-49x)+(x-7)
=(x-7)(x^2+7x+1)
3.=(x^3-4x^2)-(x^2-4x)+(x-4)
=(x-4)(x^2-x+1)
4.=(x^2+3x)(x^2+3x+2)+1
=(x^2+3x+1)-1)(x^2+3x+1+1)+1
=(x^2+3x+1)^2
5.应该是这个,不然不能分解
(xy-1)²+(x+y-2)(x+y-2xy)
(x+y-2xy)(x+y-2)+(xy-1)2
=(y2-2y+1)x2-2(y2-2y+1)x+y2-2y+1
=(y-1)2(x-1)2

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