[x(x-y)-y(x-y)+(x+y)(x-y)]÷2x其中x=2012 y=2013先化简。在求值

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[x(x-y)-y(x-y)+(x+y)(x-y)]÷2x其中x=2012 y=2013先化简。在求值

[x(x-y)-y(x-y)+(x+y)(x-y)]÷2x其中x=2012 y=2013先化简。在求值
[x(x-y)-y(x-y)+(x+y)(x-y)]÷2x其中x=2012 y=2013
先化简。在求值

[x(x-y)-y(x-y)+(x+y)(x-y)]÷2x其中x=2012 y=2013先化简。在求值
先一个一个的展开括号项,再同项合并就行了啊
[x(x-y)-y(x-y)+(x+y)(x-y)]÷2x
=[xx-xy-(xy-yy)+x(x-y)+y(x-y)]÷2x
=[xx-xy-xy+yy+xx-xy+xy-yy]÷2x
=(2xx-2xy)÷2x
=2x(x-y) ÷2x
=x-y
代入数值即可.

先去除小括号,再去大括号,就可以了

先简化代数式。前两项合并为(x-y)(x-y)与后项相加为2x(x-y),除以2x等于x-y.答案等于-1

我觉得这样更好:
原式=[(x-y)(x-y)+(x+y)(x-y)]÷2x
=(x-y+x+y)(x-y)÷2x
=2x(x-y)÷2x
=x-y
所以原式=2012-2013=-1