已知A=a²+b²-c²,B=-4a²+2b²+3c²,且A+B+C+=0 1求多项式C若a=1,b=-1,c=3,求A+B的值
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![已知A=a²+b²-c²,B=-4a²+2b²+3c²,且A+B+C+=0 1求多项式C若a=1,b=-1,c=3,求A+B的值](/uploads/image/z/3002619-3-9.jpg?t=%E5%B7%B2%E7%9F%A5A%3Da%26%23178%3B%2Bb%26%23178%3B-c%26%23178%3B%2CB%3D-4a%26%23178%3B%2B2b%26%23178%3B%2B3c%26%23178%3B%2C%E4%B8%94A%2BB%2BC%2B%3D0+1%E6%B1%82%E5%A4%9A%E9%A1%B9%E5%BC%8FC%E8%8B%A5a%3D1%2Cb%3D-1%2Cc%3D3%2C%E6%B1%82A%2BB%E7%9A%84%E5%80%BC)
已知A=a²+b²-c²,B=-4a²+2b²+3c²,且A+B+C+=0 1求多项式C若a=1,b=-1,c=3,求A+B的值
已知A=a²+b²-c²,B=-4a²+2b²+3c²,且A+B+C+=0 1求多项式C
若a=1,b=-1,c=3,求A+B的值
已知A=a²+b²-c²,B=-4a²+2b²+3c²,且A+B+C+=0 1求多项式C若a=1,b=-1,c=3,求A+B的值
A+B+C=0
所以C=-A-B
=-a²-b²+c²+4a²-2b²-3c²
=3a²-3b²-2c²