请问1/2×(1+cos2x)/2+√3/2×1/2sin2x+1=1/2sin(2x+pi/6)+5/4这一步是怎么得来的?
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![请问1/2×(1+cos2x)/2+√3/2×1/2sin2x+1=1/2sin(2x+pi/6)+5/4这一步是怎么得来的?](/uploads/image/z/3009959-71-9.jpg?t=%E8%AF%B7%E9%97%AE1%2F2%C3%97%EF%BC%881%2Bcos2x%EF%BC%89%2F2%2B%E2%88%9A3%2F2%C3%971%2F2sin2x%2B1%3D1%2F2sin%EF%BC%882x%2Bpi%2F6%EF%BC%89%2B5%2F4%E8%BF%99%E4%B8%80%E6%AD%A5%E6%98%AF%E6%80%8E%E4%B9%88%E5%BE%97%E6%9D%A5%E7%9A%84%3F)
请问1/2×(1+cos2x)/2+√3/2×1/2sin2x+1=1/2sin(2x+pi/6)+5/4这一步是怎么得来的?
请问1/2×(1+cos2x)/2+√3/2×1/2sin2x+1=1/2sin(2x+pi/6)+5/4
这一步是怎么得来的?
请问1/2×(1+cos2x)/2+√3/2×1/2sin2x+1=1/2sin(2x+pi/6)+5/4这一步是怎么得来的?