3m²-7m-4=o(用配方法解) x²+2(根号2-1)x+3-2根号2=0 (2x-5)²-(x+4)²=0x²+2(根号2-1)x+3-2根号2=0和(2x-5)²-(x+4)²=0是两个方程
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/25 20:53:36
![3m²-7m-4=o(用配方法解) x²+2(根号2-1)x+3-2根号2=0 (2x-5)²-(x+4)²=0x²+2(根号2-1)x+3-2根号2=0和(2x-5)²-(x+4)²=0是两个方程](/uploads/image/z/3012923-11-3.jpg?t=3m%26%23178%3B-7m-4%3Do%28%E7%94%A8%E9%85%8D%E6%96%B9%E6%B3%95%E8%A7%A3%EF%BC%89+x%26%23178%3B%2B2%28%E6%A0%B9%E5%8F%B72-1%29x%2B3-2%E6%A0%B9%E5%8F%B72%3D0+%282x-5%29%26%23178%3B-%28x%2B4%29%26%23178%3B%3D0x%26%23178%3B%2B2%28%E6%A0%B9%E5%8F%B72-1%29x%2B3-2%E6%A0%B9%E5%8F%B72%3D0%E5%92%8C%282x-5%29%26%23178%3B-%28x%2B4%29%26%23178%3B%3D0%E6%98%AF%E4%B8%A4%E4%B8%AA%E6%96%B9%E7%A8%8B)
3m²-7m-4=o(用配方法解) x²+2(根号2-1)x+3-2根号2=0 (2x-5)²-(x+4)²=0x²+2(根号2-1)x+3-2根号2=0和(2x-5)²-(x+4)²=0是两个方程
3m²-7m-4=o(用配方法解) x²+2(根号2-1)x+3-2根号2=0 (2x-5)²-(x+4)²=0
x²+2(根号2-1)x+3-2根号2=0和(2x-5)²-(x+4)²=0是两个方程
3m²-7m-4=o(用配方法解) x²+2(根号2-1)x+3-2根号2=0 (2x-5)²-(x+4)²=0x²+2(根号2-1)x+3-2根号2=0和(2x-5)²-(x+4)²=0是两个方程
3m²-7m-4=o
3(m^2-7/3m+(7/6)^2-(7/6)^2)-4=o
3(m-7/6)^2-3*(49/36)-4=o
3(m-7/6)^2=(49/12)+4
(m-7/6)^2=97/36
m=7/6+√97/6或m=7/6-√97/6
x²+2(根号2-1)x+3-2根号2=0
x²+2(√2-1)x+(√2-1)^2=0
(x+√2-1)^2=0
x=-√2+1
(2x-5)²-(x+4)²=0
(2x-5+x+4)(2x-5-(x+4))=0
(3x+1)(x-9)=0
x=-1/3 或 x=9