(a+b)²+|b-1∕3|=0 求(5a²b-2ab²-3ab)-(2ab+5a²b-2ab²)
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![(a+b)²+|b-1∕3|=0 求(5a²b-2ab²-3ab)-(2ab+5a²b-2ab²)](/uploads/image/z/3025550-38-0.jpg?t=%EF%BC%88a%2Bb%EF%BC%89%26%23178%3B%2B%7Cb-1%E2%88%953%7C%3D0+%E6%B1%82%EF%BC%885a%26%23178%3Bb-2ab%26%23178%3B-3ab%EF%BC%89-%EF%BC%882ab%2B5a%26%23178%3Bb-2ab%26%23178%3B%EF%BC%89)
(a+b)²+|b-1∕3|=0 求(5a²b-2ab²-3ab)-(2ab+5a²b-2ab²)
(a+b)²+|b-1∕3|=0 求(5a²b-2ab²-3ab)-(2ab+5a²b-2ab²)
(a+b)²+|b-1∕3|=0 求(5a²b-2ab²-3ab)-(2ab+5a²b-2ab²)
a+b=0
b-1/3=0
b=1/3
a=-1/3
(5a²b-2ab²-3ab)-(2ab+5a²b-2ab²)
=5a²b-2ab²-3ab-2ab-5a²b+2ab²
=-5ab
=5/9