已知函数f(x)满足f(x²-5)=lg.(x²/x²-5)①求函数f(x)的解析式②判断y=f(x)的奇偶性
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![已知函数f(x)满足f(x²-5)=lg.(x²/x²-5)①求函数f(x)的解析式②判断y=f(x)的奇偶性](/uploads/image/z/3503823-15-3.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%E6%BB%A1%E8%B6%B3f%EF%BC%88x%26%23178%3B%EF%BC%8D5%EF%BC%89%EF%BC%9Dlg.%EF%BC%88x%26%23178%3B%2Fx%26%23178%3B%EF%BC%8D5%EF%BC%89%E2%91%A0%E6%B1%82%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%E7%9A%84%E8%A7%A3%E6%9E%90%E5%BC%8F%E2%91%A1%E5%88%A4%E6%96%ADy%EF%BC%9Df%EF%BC%88x%EF%BC%89%E7%9A%84%E5%A5%87%E5%81%B6%E6%80%A7)
已知函数f(x)满足f(x²-5)=lg.(x²/x²-5)①求函数f(x)的解析式②判断y=f(x)的奇偶性
已知函数f(x)满足f(x²-5)=lg.(x²/x²-5)①求函数f(x)的解析式②判断y=f(x)的奇偶性
已知函数f(x)满足f(x²-5)=lg.(x²/x²-5)①求函数f(x)的解析式②判断y=f(x)的奇偶性
令t=x^2-5,则:x^2=t+5
由:f(x²-5)=lg.(x²/x²-5)得:
f(t)=lg.[(t+5)/t],即:
f(x)=lg.[(x+5)/x]
(x+5)/x>0
x>0或x