已知函数f(x)=asin(πx+α﹚+bcos(πx+β﹚+4,且f(2004)=3,则f(2011)=__
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![已知函数f(x)=asin(πx+α﹚+bcos(πx+β﹚+4,且f(2004)=3,则f(2011)=__](/uploads/image/z/3582208-64-8.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%3Dasin%EF%BC%88%CF%80x%2B%CE%B1%EF%B9%9A%2Bbcos%EF%BC%88%CF%80x%2B%CE%B2%EF%B9%9A%2B4%2C%E4%B8%94f%EF%BC%882004%EF%BC%89%3D3%2C%E5%88%99f%EF%BC%882011%EF%BC%89%3D%EF%BC%BF%EF%BC%BF)
已知函数f(x)=asin(πx+α﹚+bcos(πx+β﹚+4,且f(2004)=3,则f(2011)=__
已知函数f(x)=asin(πx+α﹚+bcos(πx+β﹚+4,且f(2004)=3,则f(2011)=__
已知函数f(x)=asin(πx+α﹚+bcos(πx+β﹚+4,且f(2004)=3,则f(2011)=__
此函数的周期是2,故f(0)=f(2004),f(1)=f(2011)
f(0)=asinα+bcosβ+4=3
f(1)=asin(π+α﹚+bcos(π+β﹚+4=-(asinα+bcosβ)+4=5
即f(2011)=5
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